Question

What are the solutions of this equation? 2x^2 + 16x − 8 = 0

Answer 1

`x=-4\pm2√(5)`

Explanation:

`2x^2+16x-8=0\\\\x^2+8x-4=0\\\\x=(-b\pm√(b^2-4ac))/(2a)\\ \\x=(-8\pm√((8)^2-4(1)(-4)))/(2(1))\\ \\x=(-8\pm√(64+16))/(2)\\\\x=(-8\pm√(80))/(2)\\ \\x=(-8\pm4√(5))/(2)\\ \\x=-4\pm2√(5)`