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As sin x has a period of 2, there are infinitely many solutions outside the range 0 < x < 2. In fact, any angle that is coterminal Correct: Your answer is correct. with x = 0 and x = Incorrect: Your answer is incorrect. will be a solution of the original equation.

As sin x has a period of 2, there are infinitely many solutions outside the range-example-1
User Kuljit
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1 Answer

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Solve


sin(x)=-1

Using the unitary circle below

Then, in the case of sin(x)=-1

Therefore, the solutions to the initial equation are


\begin{gathered} sin(x)=-1 \\ \Rightarrow x=(3\pi)/(2)+2\pi n;n\rightarrow integer \end{gathered}

Within the range 0

As sin x has a period of 2, there are infinitely many solutions outside the range-example-1
As sin x has a period of 2, there are infinitely many solutions outside the range-example-2
User Locohost
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