Question

Solve the equation with the quadratic formula Question 6 ?!

Answer 1

We will solve as follows! :

`p^2+3p-34=6\Rightarrow p^2+3p-40=0`

Now, we replace in the quadratic formula:

`p=\frac{-(3)\pm\sqrt[]{3^2-4(1)(-40)}}{2(1)}\Rightarrow\begin{cases}p=5 \\ p=-8\end{cases}`

So, the solutions are p = 5 and p = -8.