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If cosβ=−√2/2 β=cos−1(−2√2)beta is equal to cosine inverse of open paren negative the fraction with numerator square root of 2 and denominator 2 close parenβ is undefined.beta is undefined.β=−cos−1(−2√2)beta is equal to negative cosine inverse times open paren negative the fraction with numerator square root of 2 and denominator 2 close parenβ=±cos−1(−2√2)

If cosβ=−√2/2 β=cos−1(−2√2)beta is equal to cosine inverse of open paren negative-example-1

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Answer:


\beta\text{ = }\cos ^(-1)(-\frac{\sqrt[]{2}}{2})

Step-by-step explanation:

From the given expression, we have to get the value of the angle beta

To do this, we need to find the inverse trigonometric identity of the trigonometric identity attached to beta

Mathematically, we have this as:


\beta\text{ = }\cos ^(-1)(-\frac{\sqrt[]{2}}{2})

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