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Bdians and Degreesne Unit Circle52: The Unit Circle8096C8ght-TriangleigonometryOCOS A 1.6, tan B -0.6250uiz: Right-TriangleigonometryCOS A 1.6, tan B 0.084803 PosttestCOS A 0.8480, tan B 0.6250COS A 0.8480, tan B = 1.6inctions and Identities

Bdians and Degreesne Unit Circle52: The Unit Circle8096C8ght-TriangleigonometryOCOS-example-1
Bdians and Degreesne Unit Circle52: The Unit Circle8096C8ght-TriangleigonometryOCOS-example-1
Bdians and Degreesne Unit Circle52: The Unit Circle8096C8ght-TriangleigonometryOCOS-example-2

1 Answer

3 votes

The hypotenuse of the triangle can be determined as,


\begin{gathered} h=\sqrt[]{5^2+8^2} \\ =9.43 \end{gathered}

The cos A can be determined as,


\begin{gathered} \cos A=(AC)/(AB) \\ =(8)/(9.43) \\ =0.8480 \end{gathered}

The value of tanB can be determined as,


\begin{gathered} \tan B=(AC)/(BC) \\ =(8)/(5) \\ =1.6 \end{gathered}

Thus, option (D) is correct.

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