Answer:
The square root of 10 is between 3 and 3.5;
![\text{The value of }\sqrt[]{10}\text{ is between 3 and 3.5}](https://img.qammunity.org/2023/formulas/mathematics/college/blqv3rbfx7gpv81nst45aa308w9s261vug.png)
Step-by-step explanation:
We want to find the interval in which the root of 10 falls within.
The root of 9 is 3 and the root of 16 is 4;
![\begin{gathered} \sqrt[]{9}=3 \\ \sqrt[]{16}=4 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/moctbicaynr9j8uemy0r2976e4pfuo3uke.png)
10 is between 9 and 16, so the root of 10 is between 3 and 4;
Since the square of 3.5 is 12.25 which is also greater than 10;
![\begin{gathered} 3.5^2=12.25 \\ \text{ since;} \\ 9<10<12.25 \\ \text{then;} \\ \sqrt[]{9}<\sqrt[]{10}<\sqrt[]{12.25} \\ \text{Therefore;} \\ 3<\sqrt[]{10}<3.5 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/ii2xt60yrw7aanbflv0j6f71shwsisdguj.png)
Therefore, the square root of 10 is between 3 and 3.5;
![\text{The value of }\sqrt[]{10}\text{ is between 3 and 3.5}](https://img.qammunity.org/2023/formulas/mathematics/college/blqv3rbfx7gpv81nst45aa308w9s261vug.png)