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If a^2 + b^2 = 2ab, show that log a+b/2 = log a+ log b /2

If a^2 + b^2 = 2ab, show that log a+b/2 = log a+ log b /2-example-1

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If a²+b²=2ab therefore:


\begin{gathered} a^2+b^2-2ab=0 \\ \Leftrightarrow(a-b)^2=0 \\ \Leftrightarrow a=b \end{gathered}

Therefore:


\log (a+b)/(2)=\log (2a)/(2)=\log a=(2)/(2)\log a=(\log a+\log a)/(2)=(\log a+\log b)/(2)

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