we have
y=-3x^2+x
this is a quadratic equation (vertical parabola open dwnward)
The vertex is a maximum
Convert the eqaution in vertex form
so
y=a(x-h)^2+k
where
(h,k) is the vertex
y=-3x^2+x
Factor -3
y=-3(x^2-1/3)
Complete the square
y-1/12=-3(x^2-1/3+1/36)
rewrite as perfect squares
y-1/12=-3(x-1/6)^2
y=-3(x-1/6)^2+1/12 ------> equation in vertex form
the vertex is the point (1/6,1/12)
therefore
The maximum height of the brige is 1/12 miles and occur at 1/6 miles from the base of the bridge