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The length of a rectangle is 5 yd longer than its width.If the perimeter of the rectangle is 70 yd, find its length and width.

User Arne Lund
by
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1 Answer

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Data and background

• The length (l) of a rectangle is 5 yd longer than its width (w).

,

• The perimeter (P) of the rectangle is 70 yd.

,

• The perimeter (P) of a rectangle is given by:


P=2w+2l

where w represents the width and l the length.

Procedure

We have to build two equations with the information given.

• Equation 1


70=2w+2l

• Equation 2


l=w+5

Then, we have to replace the isolated expression of l from equation 2 in equation 1:


70=2w+2(w+5)

Simplifying the parenthesis:


70=2w+2w+10

Adding similar terms:


2w+2w=70-10
4w=60
w=(80)/(4)
w=15

Now that we know the value of w, we can calculate the value of l with equation 2:


l=15+5
l=20

Answer:

• Width: 15yd

,

• Length: 20yd

User Big Bad Baerni
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