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If a hydraulic lift uses a force of 400 N on a piston of area 0.065 m2, what is the pressure on the piston?

1 Answer

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The pressure is given by the following formula:


\begin{gathered} P=(F)/(A) \\ Where: \\ F=Force=400N \\ A=Area=0.065 \\ so: \\ P=(400)/(0.065) \\ P\approx6153.84Pa \end{gathered}

Answer:

Approximately 6153.84 Pa

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