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asked Apr 4, 2023 52.0k views

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For the reaction:

$Br_2+Cl_2\rightarrow2BrCl$

The equilibrium constant expression is:

$K_{}=(\lbrack BrCl\rbrack^2)/(\lbrack Br_2\rbrack\lbrack Cl_2\rbrack)$

Adam Tal answered Apr 10, 2023

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