Question

A car is traveling at 19.44m/s. The driver speeds up to 22m/s over a period of 0.65 seconds to pass a car in front of her. What is the acceleration of the car?

Answer 1

Given data

*The given initial speed of the car is u = 19.44 m/s

*The given final speed of the car is v = 22 m/s

*The given time is t = 0.65 s

The formula for the acceleration of the car is given as

`a=(v-u)/(t)`

Substitute the known values in the above expression as

`\begin{gathered} a=(22-19.4)/(0.65) \\ =4m/s^2 \end{gathered}`

Hence, the acceleration of the car is a = 4 m/s^2