Question

Watch help videoFind the perimeter of AIJK. Round your answer to the nearest tenth itnecessary. Figures are not necessarily drawn to scale.44H7735492034G27Submit AnswerAnswer:attempt tout of 2

Answer 1

To find the perimetr of the triangle IJK, we need to obtain the value of x.

The triangles above are similar triangles, using the ratioof similar triangle, we have

`\begin{gathered} \text{Comapring the ratio of the small triangles to the big triangles,} \\ (HF)/(KI)=(FG)/(IJ) \\ \text{Where } \\ HF=35,KI=77,FG=27,IJ=x \end{gathered}`

Substituting the values, we have

`(35)/(77)=(27)/(x)`

Then take cross product of the equation above, we have

`\begin{gathered} 35x=27*77 \\ \text{Divide both sides by 35 } \\ x=(27*77)/(35)=(27*11)/(5)=59.4 \end{gathered}`

Then, the perimeter of the triangle is sum of all the sides

`\text{Perimeter }\Delta IJK=44+77+59.4=180.4`

Therefore

The perimeter of triangle IJK is 180.4 unit