Given the function:
![y=-2+\log _2(x+1)](https://img.qammunity.org/2023/formulas/mathematics/college/m68szoxbbwx05o4minc7rr576p8hdgvhf3.png)
To compare the graphs, follow the steps below.
Step 1: Choose a value for x in order to evaluate the graphs.
Let's choose x = 0.
Then, substituting x by 0 in the equation:
![\begin{gathered} y=-2+\log _2(0+1) \\ y=-2+\log _2(1) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/by2daipxugnr2gtmoullupcfd0p6osqhyd.png)
Step 2: Solve the equation above.
Knowing that log₂(1) is 0:
![\begin{gathered} y=-2+0 \\ y=-2 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/d0tb0ssoa3maj0su5d61brw8uglhif606k.png)
So, the graph must have the point (0, -2).
Step 3: Find the point (0, -2) in the graphs.
Comparing the graphs, we can observe that only the graph drawn by Stephen contains the point (0, -2).
Answer: Stephen.