Question

a projectile is launched at height of H feet above the ground at angle of theta with the horizontal. initial velocity Vo feet per second and the path of the projectile is modeled by the paramedic equation.

Answer 1

Given,

The given parametric equation is,

`\begin{gathered} x=(v_0\text{ }cos\text{ }\theta)t \\ y=h+(v_0\text{ }\sin \text{ }\theta)t-16t^2 \end{gathered}`

Subsituting the value of

`\begin{gathered} \theta=60^(\circ)_{} \\ v_0=93\text{ feet per second} \end{gathered}`

The equation becomes,

`\begin{gathered} x=(93cos\text{ }60)t \\ x=(93*(1)/(2))t \\ x=46.5t \\ y=h+(46.5\sqrt[]{3}_{})t-16t^2 \end{gathered}`

Taking t =1,

then,

x = 46.5,

y = 111.04.

Similarly taking t = 2,

Then x = 93 and y = 190. 081

Hence, graph c is correct option