Question

I just don’t know what to put for the other 3 questions.

Answer 1

For A, there are 1 mol of N2 and 5 moles of H2 reactioning.

To state the prediction for the leftovers for A, we should find the limiting reactant.

Given the reaction, we know that for every 1 mol of N2 there's 3 moles of H2.

So, applying the stoichiometry of the reaction:

`\begin{gathered} 1molN_2\cdot(3molH_2)/(1molN_2)=3molH_2 \\ 5molH_2\cdot(1molN_2)/(3molH_2)=(5)/(3)molN_2 \end{gathered}`

Now, we could conclude that:

We have 1 mol of N2, but we actually need 5/3 mol of N2 according to the reaction. So, N2 is the limiting reactant.

We have 5 mol of H2, but we actually need only 3 moles of H2 according to the reaction. Thus, H2 is the excess reactant.

Therefore, the leftovers for A, are 5-3 = 2 moles of H2.