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In a large statistics course, 74% of the students passed the first exam, 75% of the students pass the second exam, and 61% of the students passed both exams. Find the proportion of students that passed neither exam.

User Akhil K C
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1 Answer

4 votes

Answer:

12% = 0.12

Step-by-step explanation:

The percentage of students that just pass the first exam can be calculated as the difference between the proportion of the students that pass the first exam and the proportions of the students that pass both exams. Then:

Just first exam = 74% - 61% = 13%

In the same way, the percentage of students that just pass the second exam is:

Just 2nd Exam = 75% - 61% = 14%

Now, the proportion of students that didn't pass any exam can be calculated as:

P = 100% - 13% - 14% - 61%

P = 100% - 88%

P = 12%

Because 13% passed just the first exam, 14% passed just the second exam, and 61% passed both exams.

So, 12% of students passed neither exam

User Romatthe
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