Question

A 165-Newton horizontal force is exerted upon a 7.3-kg box to move it across a level surface at a constant velocity of 2.9 m/s.The force of friction encountered by the box is

Answer 1

Given:

The horizontal force is F = 165 N

The mass of the box is m = 7.3 kg

The box moves with a constant velocity of v = 2.9 m/s

Required:

Force of friction encountered by the box.

Step-by-step explanation:

The box moves with constant velocity, so the acceleration will be zero.

The equation can be written as

`\begin{gathered} F-f=ma \\ F-f=0 \\ F=f \end{gathered}`

Here, f is the force of friction.

Thus, when an object moves with constant velocity, the applied horizontal force equals to the frictional force.

Hence, f = 165 N.

Final Answer: The force of friction encountered by the box is 165 N