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Assume that the amount of time to prepare and deliver a pizza from Pepe's pizza is normally distributed with a mean of 20 minutes and standard deviation of 5 minutes. Determine the product of pizza that were prepared and delivered. a) between 20 and 35 minutes:b) in less than 18 minutes:c) in more than 24 minutes:

Assume that the amount of time to prepare and deliver a pizza from Pepe's pizza is-example-1
User DurgaDatta
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1 Answer

5 votes

Answer:

Step-by-step explanation:

Let x represent the amount of time to prepare and deliver a pizza from Pepe's pizza. Since it is normally distributed and the population standard deviation is known, we would calculate the z score by applying the formula,

z = (x - μ)/σ

where

σ is the population standard deviation

μ is the population mean

x is the sample mean

From the information given,

μ = 20

σ = 5

a) We want to find P(20 < x < 35)

For x = 20.

z = (20 - 20)/5 = 0

From the normal distribution table, the area t the left of z = 0 is 0.5

For x = 20.

z = (20 - 20)/5 = 0

From the normal distribution table, the area to the left of z = 0 is 0.5

For x = 35.

z = (35 - 20)/5 = 3

From the normal distribution table, the area to the left of z = 3 is 0.9987

P(20 < x < 35) = 0.9987 - 0.5 = 0.4987

between 20 and 35 minutes = 0.4987

b)We want to find P(x < 18)

For x = 18,

z = (18 - 20)/5 = - 0.4

From the normal distribution table, the area to the left of z = - 0.4 is 0.3446

in less than 18 minutes = 0.3446

c) We want to find P(x > 24)

P(x > 24) = 1 - P(x ≤ 24)

For x = 24,

z = (24 - 20)/5 = 0.8

From the normal distribution table, the area to the left of z = 0.8 is 0.7881

P(x > 24) = 1 - 0.7881

P(x > 24) = 0.2119

in more than 24 minutes = 0.2119

User WSD
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