Question:
Solution:
Remember that the equation of a line is given by:
![y\text{ = mx+b}](https://img.qammunity.org/2023/formulas/mathematics/college/mfm0ccd0wy9je2uwavtbwn8cx52j97hk45.png)
where m is the slope of the line. Now, the given line is:
![y\text{ = -3x+3}](https://img.qammunity.org/2023/formulas/mathematics/college/lvklkv19xibj6yn4ufvgzwpgpuq5ylvd4s.png)
thus, the slope of this line is m= -3. Now, the problem asks us to find which of the given relationships represents a function with a lesser slope than the given line. To do this, remember that the slope of a line is given by the following equation:
![m\text{ = }(Y2-Y1)/(X2-X1)](https://img.qammunity.org/2023/formulas/mathematics/college/wpnq2pmh3iosw1lgs9vnytzc5dhqdue9xx.png)
where (X1, Y1) and (X2,Y2) are points on the line or data in a file of the table that represent a line.
therefore, we are going to calculate the slope for each relationship given in the problem:
For A:
(X1,Y1) = (0,-1)
(X2,Y2)= (-1,5)
then the slope is:
![m\text{ = }(Y2-Y1)/(X2-X1)\text{ = }(5-(-1))/(-1-0)\text{ =}(5+1)/(-1)\text{ = -6}](https://img.qammunity.org/2023/formulas/mathematics/college/mwh89yu3fgllhecwhbjlt2ainpexkosoju.png)
note that
![-6<-3](https://img.qammunity.org/2023/formulas/mathematics/college/j426v6t41l41vze8jqk6hlu7ye3ydnq5hm.png)
For B:
(X1,Y1) = (-6,-3)
(X2,Y2)= (-4,-1)
then the slope is:
![m\text{ = }(Y2-Y1)/(X2-X1)=\text{ }(-1-(-3))/(-4-(-6))=\text{ }(-1+3)/(-4+6)\text{ = }(2)/(2)\text{ = 1}](https://img.qammunity.org/2023/formulas/mathematics/college/kv9r6scu7xkz51w8vzx3gtkdjyor2m4gqj.png)
note that:
![1>-3](https://img.qammunity.org/2023/formulas/mathematics/college/hjwvlir08lrvtztof6xzg1w4j20bja7ebt.png)
For C:
(X1,Y1) = (-1,2)
(X2,Y2)= (-2,3)
then the slope is:
![m\text{ = }(Y2-Y1)/(X2-X1)\text{ = }(3-2)/(-2-(-1))\text{ = }(1)/(-2+1)=\text{ -}(1)/(1)=-1](https://img.qammunity.org/2023/formulas/mathematics/college/4ap58d8rb1xy763ranstb0gt97cqdljlbh.png)
note that:
![-1>-3](https://img.qammunity.org/2023/formulas/mathematics/college/js21loxs8xj7xj4cltakiksdhciz6miktx.png)
Finally:
For D:
(X1,Y1) = (-4,7)
(X2,Y2)= (-2,1)
then the slope is:
![m\text{ = }(Y2-Y1)/(X2-X1)=(1-7)/(-2-(-4))=\text{ }(-6)/(-2+4)=(-6)/(2)\text{ = -3}](https://img.qammunity.org/2023/formulas/mathematics/college/304mol2p9acud6siihj1t39nlc0ca76jhh.png)
note that:
![-3\text{ = -3}](https://img.qammunity.org/2023/formulas/mathematics/college/z8px83eyqoor6syuw27kc5c04woi11lfc5.png)
so that, we can conclude that the correct answer is A:
that is because the slope of graph A is lesser than the given line:
![-6<-3](https://img.qammunity.org/2023/formulas/mathematics/college/j426v6t41l41vze8jqk6hlu7ye3ydnq5hm.png)