Question

What is the index of refraction of a refractive medium if the angle of incidence in air (n=1.0003) is 87 degrees and the angle of refraction is 10 degrees?

Answer 1

Given:

The refractive index of the air, n₁=1.0003

The angle of incidence, θ₁=87°

The angle of refraction, θ₂=10°

To find:

The refractive index of the medium.

Step-by-step explanation:

From the snell's law,

`n_1\sin\theta_1=n_2\sin\theta_2`

Where n₂ is the refractive index of the medium.

On substituting the known values,

`\begin{gathered} 1.0003\sin87\degree=n_2\sin10\degree \\ \implies n_2=(1.0003*\sin87\degree)/(\sin10\degree) \\ =5.75 \end{gathered}`

Final answer:

Thus the refractive index of the medium is 5.75