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write the standard form of the equation of the circle with the given characteristics end point of diameter (-4,-1) , (4,1)​

User Alerty
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1 Answer

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16 votes

Answer:

x² + y² = 17

Explanation:

The standard equation of a circle is :

(x -h)² + ( y -k) ²= r², where (h, k) are the a coordinate of the center of the circle and r is the radius of the circle

If the end point of diameter has the coordinates (-4,-1) and (4,1)​ then the center is at the origin so we have (h= 0, k= 0)

The radius is half of the diameter so is the distance form (0,0) to (4, 1).

We can use Pythagorean Theorem to find r²

r ² = 4²+1² = 17

(x -h)² + ( y -k) ²= r², substitute what we found out

(x -0)² + ( y -0) ²= 17

x² + y² = 17

This is the equation of the circle given characteristics end point of diameter (-4,-1) , (4,1)​

write the standard form of the equation of the circle with the given characteristics-example-1
User Nanji Mange
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