100, 110, 120, 130, (Use the equation an= a1 + (n - 1)d
step 1
Find the common difference d
we have
a1=100
a2=110
a3=120
a4=130
so
a2-a1=110-100=10
a3-a2=120-110=10
a4-a3=130-120=10
the common difference d is equal to 10
d=10
step 2
substitute in teh formua
![\begin{gathered} a_n=a_1+(n-1)\cdot d \\ we\text{ have} \\ a_1=100 \\ d=10 \\ \text{substitute} \\ a_n=100+(n-1)\cdot10 \\ a_n=100+10n-10 \\ a_n=90+10n \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/v1oaqos0sjeyma7g920r6f98v3l6o4hg8d.png)
If you want to calculate the a7 term
then
For n=7
substitute in the formula
![\begin{gathered} a_7=90+10\cdot7 \\ a_7=160 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/v29ey72mupo3ov0mwqaptbepcr5w0pgd4v.png)