Question

Study the spinner below. If the wedges 2 and 5 are twice the area of the otherwedges what is the likelihood of landing on 4 or 6?23416/5A.NIO.B.A-OC.100oD. There is not enough information provided.

Answer 1

As we can see, there are 8 parts in our circle but 4 parts belong to wedge 2 and 5. Then, the probability of landing on 4 or 6 is given by

`P(4\cup5)=P(4)+P(5)`

because part 4 and part 5 are disjoint sets. Since there are 8 parts in our circle, we have

`\begin{gathered} P(4\cup5)=P(4)+p(5) \\ P(4\cup5)=(1)/(8)+(1)/(8) \end{gathered}`

which gives

`P(4\cup5)=(2)/(8)=(1)/(4)`

which corresponds to option B