Question

Question 4c. Want to clarify something I want to ask right why does it become 3y square +6y-y-2

Answer 1

Explanation:

Given the expression:

`3y^2+5y-2`

We want to write the given expression in the form:

`(ay-b)(y+c)`

That is, to factorize the expression.

When an expression is to be factorized, follow the steps below:

Step 1: Multiply the coefficient of x² and the constant.

`-2*3y^2=-6y^2`

Step 2: Find two terms that multiply to give the product -6y², and add to give the middle term, 5y. To do this, list the factors of -6: 1, 2,3, and 6

`\begin{gathered} 6y*-1y=-6y^2 \\ 6y+-y=5y \end{gathered}`

Step 3: Rewrite the middle term, 5y with those numbers.

`\begin{gathered} 3y^(2)+5y-2 \\ =3y^2+6y-y-2 \end{gathered}`

Step 4: Factor the first two and last two terms separately. Ensure that the expression in the brackets is the same.

`\begin{gathered} =3y(y+2)-1(y+2) \\ =(3y-1)(y+2) \end{gathered}`