Question

A student found that it required 25.8 mL of a 1.60 M NaOH solution to neutralize 15.0 mL of a certain H 2SO 4 solution which react according to the equation: 2 NaOH + H 2SO 4 → Na 2SO 4 + 2 H 2O. The molarity of the sulfuric acid solution

Answer 1

1) Check if the chemical reaction is balanced.

`2NaOH+H_2SO_4=Na_2SO_4+2H_2O`

2) Moles of NaOH in the reaction.

`\text{Moles of NaOH =1.60 M}\cdot\frac{25.8\text{ mL}}{\square}\cdot\frac{1\text{ L}}{1000\text{ mL}}=\text{ 0.0413 moles of NaOH}`

3) Moles of neutralized acid.

`\text{Moles of H}_2SO_4\text{ =0.0413 moles of NaOH}\cdot\frac{1molesofH_2SO_4}{2\text{ moles of NaOH}}=0.0206molesofH_2SO_4`

4) Molarity of H2SO4

`\text{Molarity of H}_2SO_4=\frac{0.0206molesofH_2SO_4}{15.0\text{ mL}}\cdot\frac{1000\text{ mL}}{1\text{ L}}=1.38MH_2SO_4`