Question

Pb(SO4)2 + LiNO3 -- Pb(NO3)4 + Li2SO4Balance this equation-how many grams of Lead (IV) sulfate is needed to produce 400 grams of lithium sulfate?

Answer 1

Step-by-step explanation

Given:

Mass of Li2SO4 = 400 g

Required: Mass of Pb(SO4)2

Solution

Step 1: Balance the equation

`Pb(SO_4)_2+4LiNO_3\rightarrow Pb(NO_3)_4+2Li_2SO_4`

Step 2: Calculate the number of moles of Li2SO4

n = m/M where n is the moles, m is the mass and M is the molar mass (109,94 g/mol)

n = 400g/109,94 g/mol

n = 3.64 mol

Step 3: Use the stoichiometry to find the moles of Pb(SO4)2

The molar ratio between Pb(SO4)2 and Li2SO4 is 1:2

Therefore the moles of Pb(SO4)2 = 3.64 x (1/2) = 1.82 mol

Step 4: Calculate the mass of Pb(SO4)2

m = n x M

m = 1.82 mol x 303,26 g/mol

m = 551.93 g

Answer

Mass of Pb(SO4)2 = 551.93 g