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What is an equation of the line that passes through the point(−5,7) and is parallel to the linex+5y=10?

1 Answer

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Answer: y = - x/5 + 6

Step-by-step explanation:

The equation of a line in the slope intercept form is expressed as

y = mx + c

where

m is the slope

c is the y intercept

The given equation is

x + 5y = 10

5y = 10 - x

5y = - x + 10

Dividing both sides by 5, we have

5y/5 = - x/5 + 10/5

y = - x/5 + 2

By comparing this equation with the slope intercept equation,

m = - 1/5

If two lines are parallel, it means that the slope of both lines are equal. This means that the slope of the line passing through the point (- 5, 7)is - 1/5. We would find the equation of the line by substituting m = - 1/5, x = - 5 and y = 7 into the slope intercept equation. We have

7 = - 1/5 * - 5 + c

7 = 1 + c

c = 7 - 1

c = 6

By substituting m = - 1/5 and c = 6 into the slope intercept equation, the equation of the line that passes through the point (−5,7) and is parallel to the line x+5y=10 is

y = - x/5 + 6

User Jens X Augustsson
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