Question

Two containers designed to hold water are side by side, both in the shape of acylinder. Container A has a diameter of 6 feet and a height of 6 feet. Container B has adiameter of 4 feet and a height of 10 feet. Container A is full of water and the water ispumped into Container B until Conainter B is completely full.After the pumping is complete, what is the volume of the empty space insideContainer A, to the nearest tenth of a cubic foot?

Answer 1

`44.0ft^3`

Step-by-step explanation

The amount of water in each container shall be calculated using

the volume of a cylinder formula

Note The volume of a cylinder is given by the formula

`V=\pi r^2h\text{ }`

where r = radius of the cylinder and h = height of the cylinder

For the first cylinder,

diameter d =6 feet,this implies that

radius r = 6/2 = 3 feet

h = 6 feet.

Therefore the volume of the Container A is calculated as thus

`\begin{gathered} V\text{ = 3.14 }*3^{2\text{ }}*6 \\ V\text{ = 3.14 }*\text{ 9 }*\text{ 6} \\ V=169.56ft^3 \end{gathered}`

And the volume of the container B as thus

r =4/2 = 2 feet, h = 10 feet

`\begin{gathered} V\text{ = 3.14 }*2^2\text{ }*\text{ 10} \\ V\text{ = 3.14 }*4\text{ }*\text{ 10} \\ V=125.6ft^3 \end{gathered}`

After the pumping is complete, the volume of the empty space inside

Container A will be

`\begin{gathered} \text{Volume of container A - Volume of container B} \\ 169.56\text{ - 125.6} \\ 44.0ft^3 \end{gathered}`