This question is related to angular frequency of oscillation
Given,
g=10 m/s²
k=80 N/m
m=0.5 kg
A=0.3 m
The angular frequency of oscillation of mass is given by
![\omega=\sqrt{(k)/(m)}](https://img.qammunity.org/2023/formulas/physics/college/199iv9wsly3s8sms82jg4ff0udn8lw845j.png)
Putting the values in the equation above
![\omega=\sqrt{(80)/(0.5)}=√(160)](https://img.qammunity.org/2023/formulas/physics/college/s9mgzf5mupwiomf2wr8jddrgpy5pe5gnn8.png)
The maximum speed of the mass is given by
![v_(max)=\omega A=√(160)*0.3](https://img.qammunity.org/2023/formulas/physics/college/l6b3y9imjuy5bdaaejwsdt2qwgrxf8rerr.png)
Result: The correct option will be A which is 3.8 m/s