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A vegetable stand sells p pumpkins for $5.00 each and s squashes for $3.00 each. On Monday, the stand sold 6 more squashes than pumpkins and made a total of $98.00. Which system of equations can be used to determine the number of pumpkins and squashes sold?

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Answer

The system of equations that can be used to solve for the number of pumpkins and squashes sold is

5p + 3s = 98

s = p + 6

After solving this, we can tell that the stand sold 10 pumpkins and 16 squashes.

Step-by-step explanation

The stand sells p pumpkins for 5 dollars each and s squashes for 3 dollars each.

This means that

The total price of p pumpkins at a rate of 5 dollars each = p × 5 = 5p dollars

The total price of s squashes at a rate of 3 dollars each = s × 3 = 3s dollars

But on Monday, we are told that the stand sold 6 more squashes than pumpkins. In mathematical terms, this means

s = p + 6

And we are told further that the total amount made from selling these p pumpkins and s squashes = 98 dollars

Amount made from selling p pumpkins and s squashes = (5p + 3s) dollars

So, we can form the system of equations now

5p + 3s = 98

s = p + 6

We can then go ahead to solve this by substituting for s in the first equation

5p + 3s = 98

s = p + 6

5p + 3 (p + 6) = 98

5p + 3p + 18 = 98

8p + 18 = 98

8p = 98 - 18

8p = 80

Divide both sides by 8

(8p/8) = (80/8)

p = 10

s = p + 6

s = 10 + 6 = 16

Hope this Helps!!!

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