Question

I need a problem question answered and explained thoroughly. Step by step Thank you!

Answer 1

Solve

`\begin{gathered} 6x^2-x<\: 2 \\ 6x^2-x-2<0 \end{gathered}`

Factor

`\begin{gathered} (2x+1)(3x-2)<0 \\ \text{then} \\ 2x+1<0 \\ 2x+1-1<0-1 \\ 2x<-1 \\ (2x)/(2)<-(1)/(2) \\ x<-(1)/(2) \end{gathered}`

and

`\begin{gathered} 3x-2<0 \\ 3x-2+2<0+2 \\ 3x<2 \\ (3x)/(3)<(2)/(3) \\ x<(2)/(3) \end{gathered}`

Therefore, Identify the intervals:

`-(1)/(2)<strong>Answer: </strong><p>Answer on a number line</p><p>Answer in interval notation</p>[tex](-(1)/(2),(2)/(3))`