Question

Solve the following system of equations.3x+5y=164x-9y=-10x =Y=

Answer 1

To simplify the calculations, you can set the following system of equations that is equivalent to the given system. Multiply the first equation by 4, and the second by 3:

`\begin{gathered} 12x+20=64, \\ 12x-27y=-30. \end{gathered}`

Subtracting the second equation for the first one, you get:

`\begin{gathered} 12x+20-12x+27y=64+30, \\ 47y=94, \\ y=(94)/(47), \\ y=2. \end{gathered}`

Substituting y=2 in the first equation and solving for x, you get:

`\begin{gathered} 3x+5(2)=16, \\ 3x+10=16, \\ 3x=16-10, \\ 3x=6, \\ x=(6)/(3), \\ x=2. \end{gathered}`

Answer:

`x=2,y=2.`