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A company produces optical-fiber cable with a mean of 0.3 flaws per 100 feet. What is the probability that there will be exactly 5 flaws in 1000 feet of cable? Round your answer to four decimal places.

User Juraj
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1 Answer

5 votes

Step 1

Given; A company produces optical-fiber cable with a mean of 0.3 flaws per 100 feet. What is the probability that there will be exactly 5 flaws in 1000 feet of cable? Round your answer to four decimal places.

Step 2

Let X denote the number of flaws in the optical cable.

The mean number of flaws per 100 feet =0.3

Thus the mean number of flaws per 1000 feet is;


\lambda=0.3*(1000)/(100)=0.3*10=3
_^(X\approx P(3))

Applying the formula


P(X=x)=(e^(-\lambda)(\lambda)^x)/(x!)
\begin{gathered} P(X=x)=(e^(-3)(3)^5)/(5!) \\ x=5 \\ P(X=5)=0.1008 \end{gathered}

Answer;


User Dawrutowicz
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