Step 1
Given; A company produces optical-fiber cable with a mean of 0.3 flaws per 100 feet. What is the probability that there will be exactly 5 flaws in 1000 feet of cable? Round your answer to four decimal places.
Step 2
Let X denote the number of flaws in the optical cable.
The mean number of flaws per 100 feet =0.3
Thus the mean number of flaws per 1000 feet is;
![\lambda=0.3*(1000)/(100)=0.3*10=3](https://img.qammunity.org/2023/formulas/mathematics/college/zl86f3zpa3dw590uu4wqlptbu4g273g734.png)
![_^(X\approx P(3))](https://img.qammunity.org/2023/formulas/mathematics/college/cjcvfgi6ltf8aly9dgf4dudrqsgycm1nl2.png)
Applying the formula
![P(X=x)=(e^(-\lambda)(\lambda)^x)/(x!)](https://img.qammunity.org/2023/formulas/mathematics/college/3a9bfzadgbnl92128qcdqa1faa90cfqoiy.png)
![\begin{gathered} P(X=x)=(e^(-3)(3)^5)/(5!) \\ x=5 \\ P(X=5)=0.1008 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/flqkkjwiw4xao0uqa173aj9byuld0i8zkl.png)
Answer;
![](https://img.qammunity.org/2023/formulas/biology/high-school/th3y35ipo1jqnb1pyz12bkyph7hz83zofb.png)