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A 1,725 kg car accelerates from 3.0 m/s for 4.4 s and reaches a velocity of 12.0 m/s. Ignoring friction, what is the applied force from the engine?

User Chasidy
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1 Answer

3 votes

Given:

The mass of the car is m = 1725 kg

The initial velocity of the car is


v_i=\text{ 3 m/s}

The final velocity of the car is


v_f=\text{ 12 m/s}

The time is t = 4.4 s

To find the applied force.

Step-by-step explanation:

The force can be calculated by the formula


F=\text{ ma}

Here, a is the acceleration.

The acceleration can be calculated as


\begin{gathered} a=(v_f-v_i)/(t) \\ =(12-3)/(4.4) \\ =2.045\text{ m/s}^2 \end{gathered}

On substituting the values, the force applied will be


\begin{gathered} F=ma \\ =1725*2.045 \\ =3527.625\text{ N} \end{gathered}

Thus, the applied force is 3527.625 N

User Shalana
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