Question

8(x – 2) + 9 < 3(x – 1) + 5xA.x < –7B.x < –3C.no solutionD.all real numbers

Answer 1

Given:

`8\mleft(x-2\mright)+9<3\mleft(x-1\mright)+5x`

To solve:

`\begin{gathered} 8\mleft(x-2\mright)+9<3\mleft(x-1\mright)+5x \\ 8x-16+9<3x-3+5x \\ 8x-7<8x-3 \\ 8x-8x<7-3 \\ 0<4 \end{gathered}`

Since, the relation is true. That is, 0 is less than 4.

Hence, the answer is, all the real numbers.