Given
The event as,
Randomly selecting a four-person committee consisting entirely of from a pool of 9 Americans and 14 Canadians.
To determine whether the individual events are independent or dependent.
Also, to find the probability of the combined event.
Step-by-step explanation:
The given individual events are independent.
Then, the probability of the combined event is,
![\begin{gathered} P(AB)=P(A)\cdot P(B) \\ =9C_4*14C_4 \\ =(9!)/((9-4)!4!)*(14!)/((14-4)!4!) \\ =\frac{9*8*7\operatorname{*}6\operatorname{*}5!}{5!(4\operatorname{*}3\operatorname{*}2\operatorname{*}1)}*\frac{14*13*12\operatorname{*}11\operatorname{*}10!}{10!(4\operatorname{*}3\operatorname{*}2\operatorname{*}1)} \\ =\frac{9*8*7\operatorname{*}6}{8*3}*\frac{14*13*12\operatorname{*}11}{12*2} \\ =3*42*7*11*13 \\ =126*77*13 \\ =126126 \end{gathered}]()
Hence, the probability of the combined event is 126126.