Question

If 2square roots x+4/3 =6 and x>0 what is the value of x

Answer 1

The given expression as;

`\frac{2\sqrt[]{x+4}}{3}=6`

Squaring both side;

`\begin{gathered} \mleft\lbrace\frac{2\sqrt[]{x+4}}{3}\mright\rbrace^2=6^2 \\ (2^2(x+4))/(3^2)=36 \\ (4(x+4))/(9)=36 \\ 4(x+4)=36*9 \\ 4x+16=324 \\ 4x=324-16 \\ 4x=308 \\ x=(308)/(4) \\ x=77 \end{gathered}`

Answer : x = 77

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