Question

H(n)=3n+4g(n)=n²-1find (h-g)(n)

Answer 1

Solve for (h - g)(n) given

h(n)=3n+4

g(n)=n^2-1

`\begin{gathered} h(n)=3n+4 \\ g(n)=n^2-1 \\ (h-g)(n)=(3n+4)-(n^2-1)* n \\ =(3n+4-n^2+1)* n \\ =(3n-n^2+5)n \\ =3n^2-n^3+5n \end{gathered}`