Question

1/4(28d+20)=d+11 Solve the linear equation

Answer 1

We have the following equation

`(1)/(4)\cdot(28d+20)=d+11`

Steps

1. Expand

`\begin{gathered} (1)/(4)\cdot28d+(1)/(4)\cdot20=d+11 \\ 7d+5=d+11 \end{gathered}`

2. substract 5 from both sides

`7d+5-5=d+11-5`

3. simplify

`7d=d+6`

4. substract d from both sides

`7d-d=d+6-d`

5. simplify

`6d=6`

6. divide by 6 and simplify

`\begin{gathered} (6d)/(6)=(6)/(6) \\ d=1 \end{gathered}`

Thus, we can see that d = 1