Question

a coast guard looks out from an observation Tower of the height 15m and sees a boat in distress at a distance of 50m what is the angle of depression of the boat from the tower ? round your answer to the nearest tenth

Answer 1

`\text{Let the angle of depression be }\theta`
`\begin{gathered} \tan (\theta)=(15)/(50)=(3)/(10) \\ \Rightarrow\theta=\tan ^(-1)((3)/(10))=16.7degrees \end{gathered}`

Hence the angle of depression is 16.7degrees