we are asked to determine the kinetic energy of an object that has a mass of 4.96g. To do that we will use the following formula:
![K=(1)/(2)mv^2](https://img.qammunity.org/2023/formulas/physics/college/89ts55elkus9wrqy6baloxb543n3yrist9.png)
Where:
![\begin{gathered} K=\text{ kinetic energy }\lbrack J\rbrack \\ m=\text{ mass }\lbrack kg\rbrack \\ v=\text{ velocity }\lbrack(m)/(s)\rbrack \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/3zcmm58u46roiexxtxdbcsf6vcbcqthfsa.png)
First, we will convert the mass into kilograms using the following conversion factor:
![1\operatorname{kg}=1000g]()
Now we multiply the mass by the conversion factor in decimal form:
![4.96g*\frac{1\operatorname{kg}}{1000g}=0.00496\operatorname{kg}]()
Now, we convert the velocity into meters per second by converting kilometers into meters. To do that we will use the following conversion factor:
![1\operatorname{km}=1000m]()
Now, we multiply the velocity by the conversion factor:
![49.1\frac{\operatorname{km}}{s}*\frac{1000m}{1\operatorname{km}}=49100(m)/(s)]()
Now, we substitute the values in the formula for the kinetic energy:
![K=(1)/(2)(0.00496)(49100(m)/(s))^2](https://img.qammunity.org/2023/formulas/physics/college/psnu9ato4njozqe2zmgthdehvdgvwri2sd.png)
Solving the operations:
![K=5.99*10^6J](https://img.qammunity.org/2023/formulas/physics/college/cvwf1iavsohyevno4mbz3pxu8ipv59dwvu.png)
And thus we have determined the kinetic energy of the meteorite.