Question

Find the equation of the axis of symmetry for this function. f(x) = -2x2 - 12x + 36

Answer 1

hello,

to find the axis of simmetry, we can use the formula below:

`x\text{ = }(-b)/(2a)`

Remembering: in a equation of 2nd degree, we have something like this:

`ax^2+bx+c`

So,

a = -2

b = -12

c = +36

Using the formula:

`\begin{gathered} x\text{ = }(-b)/(2a) \\ x\text{ = }(-(-12))/(2\cdot(-2)) \\ x=(12)/(-4) \\ x\text{ = -3} \end{gathered}`

So, the axes of simmetry pass through X when its equal to -3.