Question

Hla) = 40 gla) = 3a? - 5 Find h(g(0)

Answer 1

Given data:

`\begin{gathered} h(a)=4a \\ g(a)=3a^2-5 \end{gathered}`

The value of g(0) can be determined as,

`\begin{gathered} g(0)=3*0^2-5 \\ =0-5 \\ =-5 \end{gathered}`

The value of h(g(0)) can be determined as,

`\begin{gathered} h(g(0))=h(-5) \\ =4*(-5) \\ =-20 \end{gathered}`

Thus, option (B) is the correct solution.