Question

The set of point W(4,) X(6,2),Y(-8,16 are collinear

Answer 1

`\begin{gathered} W=(4,4) \\ X=(6,2) \\ Y=(-8,16) \\ \text{Let:} \\ (x1,y1)=(4,4) \\ (x2,y2)=(6,2) \end{gathered}`
`\begin{gathered} m=(y2-y1)/(x2-x1)=(2-4)/(6-4)=-(2)/(2)=-1 \\ y-y1=m(x-x1) \\ y-4=-1(x-4) \\ y-4=-x+4 \\ y=-x+8 \\ (-8,16) \\ 16=-(-8)+8 \\ 16=16 \end{gathered}`

Therefore, they are collinear