345,819 views
43 votes
43 votes
A high school drama club is selling tickets for the spring production. One day the president sold 12 adult tickets and 5 child tickets for a total of $169. The next day the president sold 22 adult tickets and 10 child tickets for a total of $314. Let a represent the cost of one adult ticket. Let c represent the cost of one child ticket. Which system of equations will solve for a and c? 12 a 5 c = 314. 22 a 10 c = 169. 12 a 5 c = 169. 22 a 10 c = 314. 5 a 12 c = 314. 22 a 10 c = 169. 22 a 5 c = 169. 12 a 10 c = 314.

User Martins
by
2.2k points

2 Answers

23 votes
23 votes

Answer:

12a + 5c = 169

22a + 10c = 314

Explanation:

if a = adult tickets and c = children's tickets

12 adult tickets and 5 children's tickets costs 169 dollars

12a + 5c = 169

Also, 22 adult tickets and 10 children's tickets cost 314 dollars

22a + 10c = 314

User Whmkr
by
2.4k points
15 votes
15 votes

Answer:

Its D :)

Explanation:

Have a good day.

User Lighthart
by
2.2k points