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16. What is the length of the line segment? (1pt)(-12,5)-15-10(-4,-3)A 8B V128C 16D. 260

16. What is the length of the line segment? (1pt)(-12,5)-15-10(-4,-3)A 8B V128C 16D-example-1
User Arty
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1 Answer

1 vote

We are given the following coordinates of a line segment


(-12,5)\: and\: (-4,-3)

Let us find the length of this line segment.

Recall that the distance formula is given by


d=\sqrt[]{\mleft(x_2-x_1\mright)^2+\mleft(y_2-y_1\mright)^2}

Let us substitute the given points into the above distance formula


\begin{gathered} d=\sqrt[]{(-4_{}-(-12)_{})^2+(-3_{}-5_{})^2} \\ d=\sqrt[]{(-4_{}+12_{})^2+(-3_{}-5_{})^2} \\ d=\sqrt[]{(8_{})^2+(-8_{})^2} \\ d=\sqrt[]{64^{}+64^{}} \\ d=\sqrt[]{128^{}} \end{gathered}

Therefore, the length of the line segment is √128

Option B is the correct answer.

User Ryandawkins
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