Question

the verticals of a triangle are located at (-3,-1), (2,3), (5,2). Record the triangles perimeter ti the nearest whole number.

Answer 1

the three points are

A(-3,-1) , B(2,3) & C(5,2)

`\begin{gathered} AB=\sqrt[]{41} \\ AB=6.40 \end{gathered}`

`\begin{gathered} BC=\sqrt[]{10} \\ BC=3.16 \end{gathered}`
`\begin{gathered} CA=\sqrt[]{(2-(-1)^2+(5-(-3))^2} \\ CA=\sqrt[]{3^2+8^2} \\ CA=\sqrt[]{73} \end{gathered}`
`CA=8.54`

thus, the perimeter of the triangle is

AB +BC + CA= 6.40 + 3.16 + 8.54 = 18.1

thus, the perimeter of the triangle is 18