In this case, we'll have to carry out several steps to find the solution.
Step 01:
Data
ED = 100 m
total distance run by Joe = ?
Step 02:
KE = 1/4 KA
ED = 100 m
KD = 3/4 KA
KD = KE + ED = 3/4 KA
KD = 1/4 KA + 100 = 3/4 KA
1/4 KA + 100 = 3/4 KA

KA = 100*2 = 200 m
KE = 1/4 KA = 1/4 (200) = 50 m
KD = 3/4 KA = 3/4 (200) = 150 m
Step 03:
Circumference of circle
C = 2 π r
Total distance run by Joe:
distance 1:
C1 = 2 π r = 2*π* 50m = 314.159 m
C2 = 2 π r = 2*π* 150m = 942.478 m
C3 = 2 π r = 2*π* 200m = 1256.637 m
distance 2:
AD = KA - KD = 200 m - 150 m = 50m
DE = 100 m
distance 3:
KE = 50 m
total distance run by Joe = C1 + C2 + C3 + AD + DE + KE = 2713.274 m
The answer is:
The total distance run by Joe is 2713.274 m