Given:
The perimeter of a rectangle is 84cm.
The length is 12 cm longer than the width.
Required:
We need to find the length and width of the rectangle.
Step-by-step explanation:
Let l be the length of the rectangle and w be the width of the rectangle.
The length is 12 cm longer than the width.
Add 12 to the width to get the length.
![l=12+w](https://img.qammunity.org/2023/formulas/mathematics/high-school/q95q07d68wa2m90pyc248xjsu4q3fddz1o.png)
Consider the perimeter of the rectangle formula.
![P=2(l+w)](https://img.qammunity.org/2023/formulas/mathematics/high-school/3bvd374ri4qq5bmjfcc1yqnnxj8a3xi5dx.png)
Substitute l=12+w and P =84 in the formula.
![84=2(12+w+w)](https://img.qammunity.org/2023/formulas/mathematics/high-school/51eaitxkhs1sq2vse3aol7v3xktb9ee50h.png)
![84=24+4w](https://img.qammunity.org/2023/formulas/mathematics/high-school/17hx3m0rbrykx7ar76zph4wyjdmp7vqcvq.png)
Subtract 24 from both sides of the equation.
![84-24=4w](https://img.qammunity.org/2023/formulas/mathematics/high-school/vhfpgvrqscdlna61rfwdt0zzs1njnwlayj.png)
![60=4w](https://img.qammunity.org/2023/formulas/mathematics/high-school/3uygf3qtkt2gk5kdqww5rsdcimlyto0mof.png)
Divide both sides of the equation by 4.
![15=w](https://img.qammunity.org/2023/formulas/mathematics/high-school/nxs6473fkoqsbx8s09resnl8ozz7jikwit.png)
Substitute w =15 in the equation l=12+w.
![l=12+15](https://img.qammunity.org/2023/formulas/mathematics/high-school/scujknvwtq7t0g4fde6ny8ixjkuao2fopw.png)
![l=27](https://img.qammunity.org/2023/formulas/mathematics/high-school/uqug3nw9k2efmka0gvo60enzifopd884nh.png)
Final answer:
The length of the rectangle is 27 cm.
The width of the rectangle is 15 cm.